(2/x-1) - (2-x/x)
2007-07-08 16:27:05 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2/(x-1) - (2-x)/x
Multiply the terms by x/x and (x-1)/(x-1), respectively, to place in common denominator:
2x/x(x-1) - (2-x)(x-1)/x(x-1)
(2x - (2-x)(x-1))/x(x-1)
(2x + (x-2)(x-1))/x(x-1)
(2x + x^2 - 3x + 2) / x(x-1)
(x^2 - x + 2) / x(x-1)
2007-07-08 16:34:07 · answer #1 · answered by McFate 7 · 0⤊ 0⤋
Assuming you mean
2/(x-1) - (2-x)/x
then this equals
2x / x(x-1) - (2-x)(x-1) / x(x-1)
which equals
2x - 2x +x^2 +2 -x / x(x-1)
which equals
x^2 -x + 2 / x(x-1)
which is as far as you can simplify it. Maybe I misinterpreted the question?
.
2007-07-08 16:34:34 · answer #2 · answered by tsr21 6 · 0⤊ 0⤋
(2/x-1) - (2-1) = 2/x - 2 if x is UNEQUAL to zero
2007-07-08 16:35:01 · answer #3 · answered by FifiLone 2 · 0⤊ 1⤋