2007-07-08 15:56:19 · 7 answers · asked by hannieljoseph 1 in Science & Mathematics ➔ Mathematics
3 ( x - 1 + sqrt(3)/3 ) ( x - 1 - sqrt(3)/3 )
It's not evenly factor-able, so the only way is to use the quadratic:
( -b +/- sqrt(b^2 - 4ac) ) / 2a
( - (-6) +/- sqrt((-6)^2 - 4*3*2)) / 2*3
(6 +/- sqrt(36 - 24)) / 6
1 +/- sqrt(12)/6
1 +/- sqrt(3)/3
1+sqrt(3)/3 -> (x - 1 - sqrt(3)/3) is one factor.
1-sqrt(3)/3 -> (x - 1 + sqrt(3)/3) is one factor.
3 is the final factor to yield the right coefficients
2007-07-08 16:00:30 · answer #1 · answered by McFate 7 · 1⤊ 0⤋
There are no rational factors. You need to use the quadratic formula.
if
3x²-6x+2=0 then
x=(6屉(36-24))/6
x=(6屉12)/6
x=(6±2â3)/6
x=1±1/3 â3 so the factors are
(x-1-1/3 â3)(x-1+1/3 â3)
2007-07-08 23:03:27 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
not factorable (3x-2)(x-1) will give you 3x^2-5x+2
2007-07-08 23:00:52 · answer #3 · answered by david n 1 · 0⤊ 2⤋
=(x-1)(3x-2)
check using FOIL...
(3x²-2x-3x+2)
Final answer:
(3x²-5x+2)
Correct; answer: impossible
2007-07-08 22:58:25 · answer #4 · answered by Anonymous · 0⤊ 2⤋
Not possible
2007-07-08 23:05:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
thats not factorable
2007-07-08 22:58:33 · answer #6 · answered by jon 4 · 0⤊ 1⤋
Not possible.
2007-07-09 00:20:53 · answer #7 · answered by kayedimanche 2 · 0⤊ 0⤋