(x/x+5) + (5x/x-5)
2007-07-08 15:46:40 · 4 answers · asked by seahawk_1614 1 in Science & Mathematics ➔ Mathematics
x/(x + 5) + (5x)/(x - 5)
The greatest common denominator is (x + 5)(x - 5). Therefore, multiply the numerator of the first fraction by (x - 5), multiply the numerator of the second fraction by (x + 5), and create a single denominator of (x + 5)(x - 5).
[ x(x - 5) + 5x(x + 5) ] / [ (x + 5)(x - 5) ]
Expand the numerator.
[ x^2 - 5x + 5x^2 + 25x ] / [ (x + 5)(x - 5) ]
[ 6x^2 + 20x ] / [ (x + 5)(x - 5) ]
2007-07-08 15:50:30 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
multiply it by both denominators before simplifying
mult by (x+5)/(x+5)
gives [ x + 5x(x+5)/ (x-5)] / (x+5)
multiply by (x-5)/(x-5)
gives [ x (x-5) + 5x (x+5)] / (x+5)(x -5)
combine the numerator
[ x^2 -5x + 5x^2 + 25x] = 6x^2 + 20 x = 2x ( 3x + 10)
all in all
2x (3x+10)/(x+5)(x-5)
2007-07-08 22:59:54 · answer #2 · answered by Aslan 6 · 0⤊ 0⤋
(x/x+5) + (5x/x-5)
(1 + 5) + (5 - 5)
6
The manner in which this problem was presented made it easy to solve.
.
2007-07-08 22:51:23 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
x/(x+5) + 5x/(x-5) = [x(x-5)+5x(x+5)] / [(x+5)(x-5)]
= [x^2 - 5x + 5x^2 +25x] / [(x+5)(x-5)]
= (6x^2+20x)/ [(x+5)(x-5)]
= [ 2x(3x+10)] / [(x+5)(x-5)]
2007-07-08 22:52:47 · answer #4 · answered by cllau74 4 · 0⤊ 0⤋