√196
my answer:
8²*3=64*3=196
√64*√3=√8*√8*√3-reduce
=√4*√4*√3-reduce
=√2*√2*√3
=4√3
The correct anwser is 8√3
Nopte: 8² is a perfect square of finding squaroots.
Why is my anwser wrong?
2007-07-08 14:38:59 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
14*14 is totally wrong so your wrong idoit.
2007-07-08 14:45:46 · update #1
Not that your anwser is wrong or anything, but you dont have a perfect square.
2007-07-08 14:59:24 · update #2
14 * 14 = 196
and 64 * 3 = 192 not 196, thats why your answers wrong
2007-07-08 14:43:19 · answer #1 · answered by James V 2 · 3⤊ 1⤋
64 x 3 = 192 not 196 so prob. a typo
64x 3 = 8 x 8 x 3
sq.rt 192 = 8 x sq.rt 3
2007-07-08 21:44:36 · answer #2 · answered by Aurium 6 · 0⤊ 0⤋
You found â192, not â196.
196 = 2² * 7², by factoring.
So â196 = 2*7 = 14.
Your error was 64*3 = 192.
2007-07-08 22:03:36 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
64*3=192
2007-07-08 21:42:10 · answer #4 · answered by steelydawn 2 · 3⤊ 0⤋
Square root 4 * square root 4 is not 8, its 16.
2007-07-08 21:46:33 · answer #5 · answered by Anonymous · 0⤊ 1⤋
I'm totally baffled! The second line of your work contains the answer you seek.
(rt.64)(rt3) = (rt8)(rt8)(rt3)' = 8(rt3). Note that (rt8)(rt8)=8
What baffles me is that if the question is to find rt196, the answer is 14!
rt196=(rt4)(rt49), =2x7 =14
8rt3 ==(rt64)(rt3) = rt192
2007-07-08 21:53:00 · answer #6 · answered by Grampedo 7 · 0⤊ 0⤋
Just think, if you were George Bush you would be right even when you are wrong.
Major combat operations have ended.
2007-07-08 21:41:56 · answer #7 · answered by Anonymous · 1⤊ 1⤋