What is the least number of pitches possible in one full baseball game?

Question

This is a full 9 inning game.

Answer 1

Technically, the least number of pitches that can be thrown in a complete 9 inning game is 9 per team, or 18 in total.

Care to know how this mystery could work? Unlikely scenario I know, but nonetheless this is possible....here goes....Leadoff hitter comes to the plate and the first pitch he sees he gets a triple. Before the next pitch is thrown, the runner at third attempts to steal home. The umpire rules the batter did not make an attempt to clear the baseline or impedes the catchers ability to make a tag on the runner, and therefore the batter is called out for interference. The runner returns to third base. The next 2 batters that follow are each ruled out for the same thing before another official pitch is thrown that half-inning. Therefore, 3 batters are all called for interference. 3 outs, the only pitch was the one which was hit for a leadoff triple. Repeat the same sequence for each team in each of their half-innings. Like I said, extremely unlikely, basically would never happen, but still theoretically possible.

After going on like this for 8½ innings, the first pitch thrown in the bottom of the ninth is taken for a home run. Game over. 9 pitches per team. 1 for each half-inning.

Answer 2

The home team would throw 27 pitches with each pitch getting an out and the away team throwing 25 pitches 3 in each of the first 8 innings and one pitch in the bottom of the ninth for a walk-off home run. The home run could come in any inning with the home team not even batting in the 9th. So the least number of pitches in total would be 52.

Answer 3

The answer is 52. It is based on each hitter for the visiting team swinging at the first pitch and being put out(27), each hitter on the home team hitting the first pitch for an out through 8 innings (24) and the lead off hitter in the bottom of the ninth hitting a home run on the first pitch (1)
27+24+1=52.

Answer 4

For just 1 team the answer is 27 pitches to record 27 outs.

For both teams the answer is 52 pitches for the following scenario:

Home team wins 1-0 by hitting a HR in one of the first 8 innings.

The home team gets 27 outs in 27 pitches.
The visiting team gets 24 outs in 24 pitches plus the 1 pitch for the HR.

Answer 5

For each side, 27 pitches, which would give a chance for everyone to ground out or fly out, which would come to a total of 54 pitches. But this would leave the game in a tie. So let one player hit a home run on one team and that's 55 pitches

Answer 6

I think the answer has to be 52.

Visiting team - 9 innings of one pitch per batter - 27 total.
Home team - 8 innings of one pitch per batter, plus a home run - 25. The home team would not have to bat in the bottom of the ninth.

Answer 7

Can't be 27 times two because the teams would still be tied and the game would go on. I'd propose 55. One man hits a home run, all the others are put out with one pitch and the game ends in nine innings.

Answer 8

27 pitches per team, since each team must get 27 outs in a standard baseball game. This would only be possible if each hitter hit the first pitch into an out.

Answer 9

55 total pitches.....

Visiting team.....3 pitches= 3 outs (ground out or fly out)

Home team.... 3 pitches = 3 outs (ground out or fly out)

multiply by 9 (innings) = 54 pitches

****Except one team has to hit a home run on the first pitch to make it a final. 54 pitches would make it 0-0 after nine innings

Answer 10

I say 55 pitches. Each pitcher has to at least throw 27 pitches, but the losing pitcher has thrown one additional pitch that was hit for a home run.