This is dealing with Parametric Curves.
You are given the following:
x = ln(t) y = sqrt(t) t >= 1
Eliminate the parameter to find a Cartesian equation of the curve.
I was thinking that you solve for t in the x equation and then plug it into the y equation.
But if thats right, how do you do that? E both sides?
2007-07-08 11:44:45 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
except that sqrt(e^x/2) OR sqrt(e^x) are wrong...
2007-07-08 12:01:53 · update #1
it wants the answer in the form y=__....
2007-07-08 12:12:42 · update #2
Yeah,
x = ln(t) can be written as e^x = t.
Just substitute the value of t in the Y equation.
Now Y = sqrt(e^x) or Y = e^(x/2)
2007-07-08 11:49:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x = ln(t) => t = e^x
y = sqrt(t) =>t = y^2, y is positive
t >= 1
y^2 = e^x
y = e^(x/2) because y is positive.
2007-07-08 18:49:27 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
yesh, just solve for x in the ln(t) equation to get e^x = t, and then plug that into the second equation and you should be all set from there
2007-07-08 18:50:34 · answer #3 · answered by Angad 1 · 0⤊ 0⤋
x = ln(t) y = sqrt(t) t>= 1
y^2 = t
e^x= e^ln(y^2)
e^x = y^2
2007-07-08 19:02:57 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋