See the graph of each function:
sinx = 0 ==> x= ... -2pi, -pi, 0, pi, 2pi, ...
or x = kpi where k is an integer number.
cosx = 0 ==> x = -3pi/2, -pi/2, p/2, 3pi/2...
or x = pi/2 + kpi where k is an integer number
2007-07-08 11:28:25
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answer #1
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answered by vahucel 6
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Use a graphing calculator to graph them.
sin x = 0 at x =0, pi, 2 pi, 3 pi, 4 pi, ...
cos x = 0 at x = pi/2, (3/2)pi, (5/2) pi, ...
2007-07-08 11:20:35
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answer #2
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answered by fcas80 7
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sin is 0 and pie (math symbol) and cos is pie/2 and 3pie/2 for the unit circle.
pie=3.142..... not to sure if thats correct though the pie number
2007-07-08 11:28:48
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answer #3
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answered by ezioldschool 2
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sinx = 0 when x = 0 +/-2npi and pi +/-2npi [n = 0,1,2,3...]
cos x = 0 when x= pi/2+/-2npi and 3pi/2+/-2npi [n = 0 ,1...]
2007-07-08 11:28:16
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answer #4
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answered by ironduke8159 7
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sinx=0,x=npi, n=0,1,2,3,4......
cosx=0,x=(2n+pi/2),n=0,1,2,3,4,.......
2007-07-08 11:31:53
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answer #5
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answered by Anonymous
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