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5 answers

See the graph of each function:

sinx = 0 ==> x= ... -2pi, -pi, 0, pi, 2pi, ...
or x = kpi where k is an integer number.

cosx = 0 ==> x = -3pi/2, -pi/2, p/2, 3pi/2...
or x = pi/2 + kpi where k is an integer number

2007-07-08 11:28:25 · answer #1 · answered by vahucel 6 · 0 0

Use a graphing calculator to graph them.

sin x = 0 at x =0, pi, 2 pi, 3 pi, 4 pi, ...

cos x = 0 at x = pi/2, (3/2)pi, (5/2) pi, ...

2007-07-08 11:20:35 · answer #2 · answered by fcas80 7 · 0 0

sin is 0 and pie (math symbol) and cos is pie/2 and 3pie/2 for the unit circle.
pie=3.142..... not to sure if thats correct though the pie number

2007-07-08 11:28:48 · answer #3 · answered by ezioldschool 2 · 0 0

sinx = 0 when x = 0 +/-2npi and pi +/-2npi [n = 0,1,2,3...]
cos x = 0 when x= pi/2+/-2npi and 3pi/2+/-2npi [n = 0 ,1...]

2007-07-08 11:28:16 · answer #4 · answered by ironduke8159 7 · 0 0

sinx=0,x=npi, n=0,1,2,3,4......
cosx=0,x=(2n+pi/2),n=0,1,2,3,4,.......

2007-07-08 11:31:53 · answer #5 · answered by Anonymous · 0 0

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