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A sample of gas in a 10.0 - L container exerts a pressure of 1.2 atm. Calculate the pressure exerted by the gas if the volume is changed to 15.0 L at constant temperature.

2007-07-08 06:31:22 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

We use Boyle's law
p1V1 = p2V2
1.2 x 10.0 = p2 x 15.0
p2 = 0.80 atm

2007-07-08 06:35:04 · answer #1 · answered by Dr.A 7 · 0 0

pV = nRT

Givne p and V initially cal them p0 and V0. Told T is constant. SO

p1V1 = nRT =p0V0 ---> p1 = p0 V0/V1 = 1.2*10/15 = 1.2 *2/3

p1 =0.8 atm

2007-07-08 06:36:39 · answer #2 · answered by nyphdinmd 7 · 0 0

Divide the style of grams via each and every compound's molar mass. this provides you with the style of moles of that compound, that then you definitely multiply via 22.4 to get your answer, in liters. Do the maths your self, youngster.

2016-10-20 07:21:52 · answer #3 · answered by boice 4 · 0 0

P1V1=P2V2....plug in the numbers to get ur new pressure(P2)

2007-07-11 04:17:43 · answer #4 · answered by Anonymous · 0 0

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