I DO NOT just want the answer. Please put your steps!
Factor the polynomial
48c5 + 168c4 + 147c3 completely.
A. 3c3(4c + 7)2
B. 3c2(4c + 7)2
C. 2c3(4c + 7)2
D. 4(5c + 7)2
2007-07-08 06:01:14 · 5 answers · asked by how's it going 1 in Science & Mathematics ➔ Mathematics
Factor the polynomial
48c^5 + 168c^4 + 147c^3 completely.
A. 3c^3(4c + 7)^2
B. 3c^2(4c + 7)^2
C. 2c^3(4c + 7)^2
D. 4(5c + 7)^2
2007-07-08 06:10:20 · update #1
48c^5 + 168c^4 + 147c^3
1. find a number that will divide evenly into all 3 coefficients, then take out the maximum number of "c" from each monomial
3c^3(16c^2+56c+49)
2. factor the equation inside the parenthesis - leaving the 3c^3 alone
3c^3(4c+7)(4c+7) then simplify
YOUR ANSWER --> --> --> 3c^3(4c+7)^2
2007-07-08 06:42:54 · answer #1 · answered by bnhawk03 3 · 0⤊ 0⤋
Take out a common factor
3c3(16c2+56c+49)
Simplify the quadratic equation in the bracket.
3c3(4c+7)(4c+7)
2007-07-08 13:10:01 · answer #2 · answered by mymichelle88 1 · 0⤊ 0⤋
the numerical coefficients have a common factor of 3; the lowest exponent on the common variable factors of c is 3, so factor out 3c^3:
3c^3 (16c² + 56c + 49)
the quadratic trinomial is a perfect square: 16c² is the square of 4c, 49 is the square of 7, and 56c is twice the product of 4c and 7, so
3c^3 (4c + 7)²
2007-07-08 13:09:23 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
48c5 + 168c4 + 147c3
=3c^3(16c^2 + 56c + 49)
=3c^3(4c + 7)^2
A. 3c3(4c + 7)2
2007-07-08 13:12:26 · answer #4 · answered by fofo m 3 · 0⤊ 0⤋
48c^5+168c^4+147c^3
=3c^3(16c^2+56c+49)
=3c^3[(4c)^2+2(4c)(7)+(7)^2]
=3c^3(4c+7)^2
A is the answer.
2007-07-08 13:17:48 · answer #5 · answered by God_Of_War 2 · 0⤊ 0⤋