Factor: y2 - 16
2007-07-08 05:30:04 · 8 answers · asked by andy s 2 in Science & Mathematics ➔ Mathematics
(y-4)(y+4)
2007-07-08 05:33:31 · answer #1 · answered by fofo m 3 · 0⤊ 0⤋
its actually 2y-16, and then you bring 16 to the other side which you end up with 2y=16 and then you want the y by itself so you divide both sides by 2, and you end up getting y=4. that's how you would solve it, but factoring it, it would be 2(y-4).
and if its y2-16, it be (y-4) (y+4)
2007-07-08 05:35:49 · answer #2 · answered by P711 1 · 0⤊ 1⤋
a^2-b^2=(a+b)(a-b)
Y^2-16=(y+4)(y-4) because 4^2=16
Did you mean y^2 (square of y) when you said y2?
2007-07-08 05:38:09 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋
y²-16 = y²-4²
= (y+4)(y-4)
Therefore y = ±4
2007-07-08 05:37:54 · answer #4 · answered by robinho_83 1 · 0⤊ 0⤋
a^2 - b^2 = a^2 - ab + ab - b^2 = a(a-b) +b(a-b) = (a+b)(a-b)
So y^2 - 16 = (y+4)(y-4)
2007-07-08 05:34:27 · answer #5 · answered by astrokid 4 · 0⤊ 0⤋
Y-yes
2007-07-08 05:33:43 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the formula to do this is (a^2-b^2)=(a-b)(a+b)
your problem is y^2-16
so think of it, wat y could be equal to? a? yes.
y=a, so y is your a number
so how about 16? is it b^2? yeah! but wat number have square equal to 16? that's 4, so 4 is your b number.
so followed the formula, you'll have:
(a^2-b^2)=(a-b)(a+b)
(y^2-4^2)=(y-4)(y+4) (Substitute y for a, 4 for b)
2007-07-08 06:33:08 · answer #7 · answered by God_Of_War 2 · 0⤊ 0⤋
(y - 4).(y + 4)
Check
y.(y + 4) - 4.(y + 4)
y² + 4y - 4y - 16
y² - 16 (as required)
2007-07-08 08:26:57 · answer #8 · answered by Como 7 · 0⤊ 0⤋