In February, you have a balance of $270 in your bank account. Each month you deposit $45. Let January = 1, February = 2, and so on. Write an equation for this situation. Use the equation to find the balance in June.
y – 270 = 45(x – 2) ; $450
y = 45(x – 4); $270
y = 45(x – 4); $180
y – 270 = 45x; $45
2007-07-08 04:11:06 · 5 answers · asked by Chealsea Y 1 in Science & Mathematics ➔ Mathematics
You start out with $270 in February (the second month) and you deposit $45 each month after that. So, in March (month 3) you add $45 to the account. In April (month 4), you add another $45, so now you have added $90, or 2 * $45. You can find an equation by subtracting 2 from the number of the month, and then multiplying that by $45, and then you add that to your original starting balance ($270), so
y = 270 + (45)(x -2)
You can subtract 270 from both sides to get
y - 270 = (45)(x - 2)
This looks like your first option is your answer. If you plug in the number of the month of June (6), you can get your balance:
y - 270 = (45)(6 - 2)
y - 270 = (45)(4)
y - 270 = 180
y = 450
So, you have $450 in June
2007-07-08 04:24:51 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Given: $270 the bank balance in February.
$45 the deposit in each subsequent month.
Problem:
To create an algebraic equation to determine the
bank balance at the end of June.
Assumptions:
Let J = the balance at the end of June.
Let F = the balance in February.
Let M3, M4, M5, and M6 the monthly deposit for
March, April, May and June, respectively.
Solution (Using Substitution Method):
The Equation:
J = F + M3 + M4 +M5 + M6
Substituting the given values:
J = 270 + 45 +45 + 45 + 45
J = 450
Note: We could have gotten the answer 450 easily by adding
the numbers 270 + 45 + 45 + 45 +45 in our minds. But that was not our goal. Our goal was what equation can we create to arrive at the solution or answer of 450.
I hope the exercise did not bore you but instead showed you
the beauty of being able to express in equation form the mathematical problem on hand.
2007-07-08 04:45:54 · answer #2 · answered by the lion and the bee 3 · 0⤊ 0⤋
The first one is the answer.
y = 270 + 45(x - 2) or y - 270 = 45(x - 2)
where x is the month and y is the balance.
2007-07-08 04:45:25 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
I'll use arithmetic progression
Using T=a + (n-1) d
since in February you have 270, then
270 = a + (2-1)45
a + 45 = 270
a= 225
Since June is 6th month
T = 225 + (6-1)45
= 225 + 225 = 450
The answer is $450.
Using the formula the total can be calculated indefinitely.
2007-07-08 04:19:00 · answer #4 · answered by Antish 2 · 0⤊ 0⤋
y – 270 = 45(x – 2) ; $450
2007-07-08 04:18:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋