(4x^10 + 4x^9 + 20x^8 +16x^7) divide by 4x^7
2007-07-08 02:37:50 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This is a rather simple equation to solve.
1. 4x^10 + 4x^9 + 20x^8 + 16x^7 / 4x^7
Since you're dividing by x^7 it's the same as subtracting x^7 from the exponents above them as long as they've got the same variable which they do. So it would be reduced to the following.
2. 4x^3 + 4x^2 + 20x + 16 / 4
Now we simply divide all of the whole numbers there by 4 and get the following.
3. x^3 + x^2 + 5x + 4 which is the final answer.
2007-07-08 02:52:21 · answer #1 · answered by dkillinx 3 · 0⤊ 0⤋
x^3 + x^2 + 5x +4
2007-07-08 09:47:58 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋
=x^3+x^2+5x+4
2007-07-08 09:42:08 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
x^3+x^2+5x+4
2007-07-08 09:42:14 · answer #4 · answered by Mr. me 2 · 0⤊ 0⤋
= x³ + x² + 5 x + 4
That`s it---no simplification required!
2007-07-08 10:23:15 · answer #5 · answered by Como 7 · 0⤊ 0⤋
0.856 is the answer
2007-07-08 09:52:22 · answer #6 · answered by surfer 1 · 0⤊ 0⤋