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(x^2 - 2x) (x^2 -5x +4)

2007-07-08 02:35:06 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

(x^2 -2x)( x^2 - 5x + 4 )
= x^4 - 5x^3 + 4x^2 - 2x^3 + 10x^2 - 8x
= x^4 - 7x^3 + 14x^2- 8x

2007-07-08 02:56:19 · answer #1 · answered by CPUcate 6 · 0 0

x^4 - 5x^3 + 4x^2 - 2x^3 + 10x^2 - 8x

x^4 -7x^3 +14x^2 - 8x = 0

2007-07-08 02:39:51 · answer #2 · answered by Anonymous · 0 0

(x^2 - 2x) (x^2 -5x +4)
=x^4-5x^3+4x^2-2x^3+10x^2-8x
=x^4-7x^3+14x^2-8x

2007-07-08 02:40:45 · answer #3 · answered by iyiogrenci 6 · 0 0

2. (x^2 - 2x)(x^2 - 5x + 4) = [x(x - 2)] [(x - 1)(x - 4)] = x(x-2)(x-1)(x-4)

2016-05-21 03:59:45 · answer #4 · answered by ? 3 · 0 0

Expand then factor and get

x*(x-1)*(x-2)*(x-4)

2007-07-08 02:47:17 · answer #5 · answered by ? 5 · 0 0

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