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(√3 / √6-1) - ( √3 / √6+1)

Sorry this is correct. The square root of 3 divided by the square root of 6-1. subtract the square root of 3 divided by the square root of 6+

2007-07-07 17:34:35 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Cross multiplying your equation gives:
(√3(√6 + 1) - √3(√6 - 1)) / ((√6 - 1) * (√6 + 1))
= (√3(√6 + 1) - √3(√6 - 1)) / 5
= (√18 + √3 - √18 + √3) / 5
= (2√3) / 5

2007-07-07 17:45:27 · answer #1 · answered by Astroboy 2 · 0 0

No. its NOT correct. √(6-1) or (√6) -1. Since I assume you'd do the math if it were √(6-1) {= √5 } what you should have written is: {√3 / ([√6]-1)} - {√3 / ([√6]+1) }. It just leaves nothing ambiguous there.
anyway. multiply first term by (√6+1)/(√6+1) and second term by (√6-1)/(√6-1). You are absolutely right I didn't use a double set of parenthesis, either. But by now you and I know what we're talking about. This will give you a common divisor (5) and all you have to do is multiply the terms out in the numerator and add (or subtract) to simplify.

2007-07-07 17:49:08 · answer #2 · answered by Anonymous · 0 0

= [√3 (√6 + 1) - √3.(√6 - 1) ] / [ (√6 - 1).(√6 + 1) ]
= 2.√3 / [ (√6 - 1).(√6 + 1) ]
= 2.√3 / (6 - 1)
= 2.√3 / 5

2007-07-07 20:44:12 · answer #3 · answered by Como 7 · 0 0

{√3/(√6 -1)} - {√3/(√6 + 1)}
If I understand the problem, the 1st thing to do is multiply by common denominator, (√6 -1)(√6 + 1):

{(√6 - 1)(√6 + 1)}{√3/(√6 -1)} - {(√6 - 1)(√6 +1)}{√3/(√6 + 1)}

This gives you:

(√6 + 1)(√3) - (√6 -1)(√3)
----------------------------------
(√6 +1)(√6 -1)

Simplify:

(√18 + √3 -√18 +√3)
--------------------------
(√36 - 1)

(2√3)/5

2007-07-07 18:02:50 · answer #4 · answered by gm 2 · 0 0

I updated my answer on your previous post to address the change in the problem. Check it out.

2007-07-07 17:45:43 · answer #5 · answered by beabria 2 · 0 0

damn are you in summer school

2007-07-07 17:37:58 · answer #6 · answered by Esmerelda 2 · 0 1

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