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(x^4 - 4x ^2 - 5) (x ^2 - x +2)

2007-07-07 17:31:43 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

= x^6 - x^5 + 2x^4 - 4x^4 + 4x^3 - 8x^2 - 5x^2 + 5x - 10
= x^6 - x^5 - 2x^4 + 4x^3 -13x^2 + 5x - 10

2007-07-07 17:34:52 · answer #1 · answered by cheeseballer 3 · 0 0

x^6 - x^5 + 2 x^4 - 4 x^4 + 4 x³ - 8 x² - 5x² + 5x - 10
= x^6 - x^5 - 2 x^4 + 4 x³ - 13 x² + 5 x - 10

2007-07-08 03:49:31 · answer #2 · answered by Como 7 · 0 0

x^4-4x^2-5
x^2-x+2
_________________

x^6-x^5-2x^4+4x^3-13x^2+5x-10

2007-07-08 00:39:38 · answer #3 · answered by Dave 2 · 0 0

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