Geometry Help!?

1 ⤊

In parallelogram ABCD, BC = 8, DC = 12, and measure of angle D is 50 degrees. Find the area of the parallelogram to the nearest tenth.

2007-07-07 12:39:00 · 3 answers · asked by Zainab 2 in Science & Mathematics ➔ Mathematics

3 answers

height = 8sin50. so Area = 96 sin50 = 73.5 unit^2

2007-07-07 12:46:50 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

The formula for the area of a parallelogram is the same as the formula for the area of a rectangle, except you tack on the sine of one of the angles at the end. So Area = 8*12*sin(50).

2007-07-07 19:44:06 · answer #2 · answered by Bill Lumbergh 4 · 1⤊ 0⤋

h = 8 sin 50 = 6.1284
area = CD ( h ) = 12 (6.1284 )

area = 73.54

area = 73.5 . . . . . as requested

2007-07-07 19:51:02 · answer #3 · answered by CPUcate 6 · 0⤊ 0⤋