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3 answers

Let's call this sum 1+s, where s is the square root part.

x = 1+s

But we know that s^2 is the same as 1+s (the stuff inside the first square root is identical to the original sum).

s^2 = 1 + s
s^2 - s - 1 = 0

Using the quadratic:

s = (1 +/- sqrt(1 + 4))/2
s = (1 + sqrt(5))/2

Since x=1+s, and ignoring the negative solution:

x = 1 + (1+sqrt(5))/2
x = 3/2 + sqrt(5)/2

2007-07-07 10:00:16 · answer #1 · answered by McFate 7 · 0 1

4

2007-07-07 10:02:06 · answer #2 · answered by Anonymous · 0 1

xxx+2sqrt(1-1)=0-sex<4U

2007-07-07 10:00:20 · answer #3 · answered by Anonymous · 1 2

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