Solve the equation 5y+10x=30 for y
A y=2x + 6
B y= -2x + 6
C y= 2x -6
D y= -2x -6
2007-07-07 09:44:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5y + 10x = 30
Transpose 10x
5y + 10x - 10x = - 10x + 30
5y = - 10x + 30
Divide both sides of the equation by 5
5y / 5 = - 10x / 5 + 30 / 5
y = - 2x + 6
- - - - - - - -s-
2007-07-07 10:57:54 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
5y+10x=30
leaving y on the left side of the equation we've got:
5y=30-10x
then we take the 5 to the right side to divide and we've got:
y=(30-10x)/5
dividing every part of the difference we've got:
y=30/5-10x/5
and then:
y=6-2x=-2x+6 the answer is the B option.
2007-07-07 16:55:21 · answer #2 · answered by patoo_zz 2 · 0⤊ 0⤋
5y = 30 -10x
y = 6 - 2x
2007-07-07 16:47:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
5y + 10x = 30
5y = 30 - 10x
y = (30 - 10x)/5
y = 6 - 2x
or
y = -2x + 6
The answer is B
2007-07-07 16:51:44 · answer #4 · answered by drochem 5 · 0⤊ 0⤋
5y+10x=30 subtract 10x
5y=30-10x divide by 5
y=6-2x
B. y=-2x+6
Hope that helps.
2007-07-07 16:51:33 · answer #5 · answered by Shauna 3 · 0⤊ 0⤋