Whats the answer to this quadratic equation?

Question

2(x-1)=x(2x+2)

How do i do this problem?

Answer 1

2(x-1) = x(2x+2)
multiply the 2 and x in each side

2x-2 = (2x^2) + 2x
and you get this
then bring all the numbers and variables (x's) together onto one side to make the other side equal 0

0 = (2x^2) + 0x + 2
and you get this
then plug in the numbers into the quadratic equation and you get the square root of -16 and then that divided by 4

because you cant get the square root from a negative number i guess the answer would ±i1 which is the same things as ±i

sq. root of 16 = 4 divided by 4 = 1 so ±i or THE ANSWER IS JUST no solution because of the negative.

Answer 2

Distribute, then get everything on the right side of the equation first, like this:

2(x-1)=x(2x+2)
Distribute
2x-2=2x^2+2x
Subtract 2x from one side
-2=2x^2
Divide by 2
-1=x^2
Squareroot

+/- i = x (because i = squareroot of -1)

Answer 3

2x - 2 = 2x² + 2x
2x² + 2 = 0
2 (x² + 1) = 0
x = ± i

Answer 4

That's easy(and I'm not evan that great at math)

multiply each side first to get rid of the parenthesis then from there it's basic algebra.

2x-1=2xsquared+2x

the two 2x's cancel and your left with -1=2xsquared

Answer 5

2(x-1) = x(2x+2)
2x - 2 = 2x² + 2x
-2 = 2x²
x² = -1
x = ±√-1 = ±i