Help rightnow please?

Question

Please help here?
Solve the inequality and explain how you found the solution.
x^2-2x-5>0

This is a Pre-Calculus problem.

Answer 1

first solve x² - 2x - 5 = 0
x² - 2x = 5
x² - 2x + 1 = 5 + 1
(x - 1)² = 6
x - 1 = ±√6
x = 1 ± √6

The graph of y = x² - 2x - 5 is a parabola that opens upward and crosses the x axis at x = 1 ± √6. So y > 0 when x > x = 1 + √6 and when y < x = 1 - √6. In interval notation, your solution is (-∞,1 - √6) union (1 + √6, ∞)

Answer 2

You need to use the quadratic formula to find the solution to the equation x^2-2x-5=0.
Suppose you get x = a and x = b as solutions, then
x^2-2x-5=(x-a)(x-b)>0
Case 1: When x-a>0 and x-b>0 then (x-a)(x-b)>0
Find these values of x such that both inequalities x-a>0 and x-b>0 are true.
Case 2: When x-a<0 and x-b<0 then (x-a)(x-b)>0
Find these values of x such that both inequalities x-a<0 and x-b<0 are true.
The solution will be the set of values of x in cases 1 and 2.
Try it.

Answer 3

Step 1. Find the boundaries, using quadratic formula
x = (2±√24)/2 = 1±√6
Step 2. Since y = x^2-2x-5 opens up, the solution is
x < 1-√6
or
x > 1+√6