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please help

2007-07-07 05:22:42 · 11 answers · asked by Tiana R 1 in Science & Mathematics Mathematics

11 answers

6c + d x 6c - d = 36 c^2 - d^2

2007-07-07 05:25:55 · answer #1 · answered by Swamy 7 · 0 0

This is called the difference of two squares
so (a+b)(a-b) =a^2 - b^2
so (6c+d)(6c-d) =36c^2 -d^2

2007-07-07 05:30:35 · answer #2 · answered by Psygnosis 3 · 0 0

Remember multiply each term in the first bracket by each term in the second bracket.
hence (6c+d)(6c-d) = 36c^2 -6cd + 6cd -d^2
= 36c^2 - d^2

2007-07-07 05:34:10 · answer #3 · answered by tony10 1 · 0 0

Use the identity a^2-b^2=(a+b)(a-b)
(6c+d)(6c-d)=(6c)^2-(d)^2
=36c^2-d^2

2007-07-07 05:27:30 · answer #4 · answered by iyiogrenci 6 · 0 0

(6c+d)(6c-d) you would be able to desire to FOIL. this implies multiply the 1st, interior, exterior, and final areas of each and every binomial. you wind up with this: 36c^2 - 6cd + 6cd - d^2 simplifies to: 36c^2 - d^2 interior the subsequent one, it is the comparable concept. This time, basically multiply all the flaws of the 1st area to all the flaws of the subsequent one: (x-3y)(x^2+3y+9y^2) x^3+3yx+9xy^2-3yx^2-9y^2-27y^3

2016-12-10 04:49:53 · answer #5 · answered by newcomer 4 · 0 0

(6c+d)(6c-d)
=36c^2-d^2
use special multiplication (a+b)(a-b)=a^2-b^2

2007-07-07 05:30:07 · answer #6 · answered by chris 3 · 0 0

Remember FOIL

F = multiply first terms
O = multiply outer terms
I = multiply inner terms
L = multiply last terms

Then simply if possible. Always watch your signs.

2007-07-07 05:27:27 · answer #7 · answered by Lady Geologist 7 · 1 0

(6c+d)(6c-d)
=(36c^2-d^2)

2007-07-07 05:26:32 · answer #8 · answered by fofo m 3 · 0 0

FOIL it!
(first, inner, outer, last)

36c^2 + 6cd - 6cd - d^2 = 36c^2 - d^2

2007-07-07 05:26:56 · answer #9 · answered by abbyful 7 · 0 0

= 36c² - 6cd + 6cd - d²
= 36 c² - d²

2007-07-07 05:43:30 · answer #10 · answered by Como 7 · 0 0

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