6c + d x 6c - d = 36 c^2 - d^2
2007-07-07 05:25:55
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answer #1
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answered by Swamy 7
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This is called the difference of two squares
so (a+b)(a-b) =a^2 - b^2
so (6c+d)(6c-d) =36c^2 -d^2
2007-07-07 05:30:35
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answer #2
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answered by Psygnosis 3
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Remember multiply each term in the first bracket by each term in the second bracket.
hence (6c+d)(6c-d) = 36c^2 -6cd + 6cd -d^2
= 36c^2 - d^2
2007-07-07 05:34:10
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answer #3
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answered by tony10 1
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Use the identity a^2-b^2=(a+b)(a-b)
(6c+d)(6c-d)=(6c)^2-(d)^2
=36c^2-d^2
2007-07-07 05:27:30
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answer #4
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answered by iyiogrenci 6
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(6c+d)(6c-d) you would be able to desire to FOIL. this implies multiply the 1st, interior, exterior, and final areas of each and every binomial. you wind up with this: 36c^2 - 6cd + 6cd - d^2 simplifies to: 36c^2 - d^2 interior the subsequent one, it is the comparable concept. This time, basically multiply all the flaws of the 1st area to all the flaws of the subsequent one: (x-3y)(x^2+3y+9y^2) x^3+3yx+9xy^2-3yx^2-9y^2-27y^3
2016-12-10 04:49:53
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answer #5
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answered by newcomer 4
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(6c+d)(6c-d)
=36c^2-d^2
use special multiplication (a+b)(a-b)=a^2-b^2
2007-07-07 05:30:07
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answer #6
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answered by chris 3
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Remember FOIL
F = multiply first terms
O = multiply outer terms
I = multiply inner terms
L = multiply last terms
Then simply if possible. Always watch your signs.
2007-07-07 05:27:27
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answer #7
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answered by Lady Geologist 7
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(6c+d)(6c-d)
=(36c^2-d^2)
2007-07-07 05:26:32
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answer #8
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answered by fofo m 3
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FOIL it!
(first, inner, outer, last)
36c^2 + 6cd - 6cd - d^2 = 36c^2 - d^2
2007-07-07 05:26:56
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answer #9
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answered by abbyful 7
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= 36c² - 6cd + 6cd - d²
= 36 c² - d²
2007-07-07 05:43:30
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answer #10
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answered by Como 7
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