please help
2007-07-07 05:14:24 · 5 answers · asked by Tiana R 1 in Science & Mathematics ➔ Mathematics
2x^2+13x+20
=2x^2+8x+5x+20
=2x(x+4)+5(x+4)
=(x+4)(2x+5)
2007-07-07 05:22:15 · answer #1 · answered by alpha 7 · 1⤊ 0⤋
2x^2 + 13x + 20
= 2x^2 + 8x + 5x + 20
= (2x^2 + 8x) + (5x + 20)
= 2x(x +4) + 5(x + 4)
= (2x + 5) (x + 4)
Explanation:
1. Find two numbers when you multiply the coefficient of x^2 and the constant will give you the result of x when added (ie. 2 by 20 is 40 but when added will not give the coefficient of x, but 8 by 5 will give 40 and when added will give the coefficinet of x which is 13. Thereby, the two numbers happen to be 5 and 8). NB: attach the x symbol to the two numbers.
2. Select one of the gained number that will work out with the coefficient of x^2 and the other with the constant.
3. Factorize what you had in (2) above
4. Group like terms in one bracket and the other in seperate bracket (ie. 2x(x +4) + 5(x + 4) to give you (2x + 5) (x + 4) ).
2007-07-07 05:32:33 · answer #2 · answered by kissehaggudey 2 · 0⤊ 0⤋
2x^2+13x+20 = (2x+5)*(x+4)
2007-07-07 05:22:42 · answer #3 · answered by nyphdinmd 7 · 1⤊ 0⤋
(2x+5)(x+4)
2007-07-07 05:18:28 · answer #4 · answered by Anonymous · 1⤊ 0⤋
N/A. Cannot be factored.
2007-07-07 05:19:28 · answer #5 · answered by g_miller_36 2 · 0⤊ 3⤋