5x+12-3x=17
2x=5
x=2/5
Now, putting the value of x
5*5/2 + 3{4- (5/2)} = 25/2 +3* { (8-5)/2}
=> 25/2 + 9/2
=>17 ans.
So, its the right equation
2007-07-07 05:19:56
·
answer #1
·
answered by fha_chafzeto 2
·
0⤊
0⤋
5x + 3(4 - x) = 17
5x + 12 - 3x = 17
2x = 17 - 12 = 5
x = 5/2
2007-07-07 05:10:31
·
answer #2
·
answered by Swamy 7
·
0⤊
0⤋
First step, multiply your way out of those brackets.
5x+3(4-x)= 17
becomes
5x+12-3x=17
Since you have 5x-3x which leaves 2x, you now have
2x+12=17
Take the 12 to the other side of the equation and you have to change its sign. This leaves
2x=17-12
and thus
2x=5
Since you can now divide each side of the equation by 2, you are left with
2x/2=5/2
Any number divided by itself leaves 1, that's the whole idea of dividing by 2 at this point. Thus as 2x/2=x and 5/2=2.5, we now see
x=2.5
and there you have your answer.
I hope this helps; please feel free to drop me a line if you want or need any more advice on this kind of thing.
2007-07-10 07:40:55
·
answer #3
·
answered by general_ego 3
·
0⤊
0⤋
5x + 12 - 3x = 17
2x = 5
x = 5 / 2
2007-07-07 05:44:33
·
answer #4
·
answered by Como 7
·
0⤊
0⤋
That is the correct answer
first you have to solve for x
5x+3(4-x)=17 (distribute)
5x+12-3x=17 (combine like terms)
2x+12=17 (subtract 12 from 17)
2x=5 (divide 5 by 2)
x=2.5
now plug the value for x (2.5) in the equation
5(2.5)+3(4-2.5)=17 (distribute)
12.5+3(1.5)=17 (distribute(multiplication)
12.5+4.5=17 (add)
17=17
so your answer was right
2007-07-07 05:19:12
·
answer #5
·
answered by bre 1
·
0⤊
0⤋
5x+12- 3x=17
2x= 17-12
x=5/2
2007-07-08 07:41:01
·
answer #6
·
answered by ~*tigger*~ ** 7
·
0⤊
0⤋
5x+3(4-x) = 17
5x+12-3x = 17
5x-3x = 17-12
2x = 5
x = 5/2
2007-07-07 05:09:08
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
5x+12-3x=17
2x=5
x=5/2
2007-07-07 05:07:29
·
answer #8
·
answered by gordonmorrison 6
·
0⤊
0⤋
5x + 3(4 - x) = 17
5x + 12 - 3x = 17
5x - 3x = 17 -12
2x = 5
x = 5/2
x = 2.5
2007-07-11 05:02:09
·
answer #9
·
answered by Jun Agruda 7
·
2⤊
0⤋
5x+12-3x=17
2x=17-12
2x=5
x=5/2
2007-07-07 05:16:13
·
answer #10
·
answered by chris 3
·
0⤊
0⤋