2007-07-07 03:59:29 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x^7)^-3
=x^(7*-3).......since (x^a)^b = x^ab
=x^-21
=1 / x^21.......since x^-a =1 / x^a
the end
.
2007-07-07 04:03:22 · answer #1 · answered by The Wolf 6 · 1⤊ 0⤋
First, we multiply the exponents to get x^-21, then to eliminate the negative exponent, we move it into the denominator to get an answer of 1/(x^21)
2007-07-07 11:04:17 · answer #2 · answered by Mr. me 2 · 1⤊ 0⤋
Rule is (x^m)^n = x^(mn)
Thus (x^7)^( - 3) = x^(- 21) = 1 / x^21
2007-07-10 17:33:50 · answer #3 · answered by Como 7 · 0⤊ 0⤋
tip:
a^(-b) = 1 /(a^b)
(a^b)^(c) = a^(b*c)
(x^7)^(-3)
= x^( 7 * (-3))
= x^ (-21)
= 1/(x^21)
2007-07-07 20:58:03 · answer #4 · answered by buoisang 4 · 0⤊ 0⤋
hey, nice weird signs , i might be in grade 9, but maths aint my thing and i dint study that part of maths yet , i am just lucky for now:P
2007-07-07 11:14:36 · answer #5 · answered by ~Insanity Has Taken Over~ 3 · 1⤊ 0⤋