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2007-07-06 15:24:57 · 5 answers · asked by michael 1 in Science & Mathematics Mathematics

5 answers

Though you didn't state is, I think your question is: "What is the value of b?"

Put another way, the question is, "Which base b, when raised to the 5th power, equals 5?"

That's the same as the solution to this:

b^5 = 5

Take the 5th root of both sides, and you get this:

b = 5^(1/5)

So b is about 1.38

2007-07-06 15:33:22 · answer #1 · answered by RickB 7 · 0 0

Hey there!

Here's the answer.

logb 5=5 --> Write the problem.
b^logb 5=b^5--> Let b be the base of each side of the equation.
5=b^5 --> Use the exponential-logarithmic inverse properties.
5^1/5=(b^5)^1/5 --> Take the fifth root on each side of the equation.
5^1/5=b --> Simplify the above equation.
b=5^1/5 --> Use the symmetric property of equality i.e. if a=b, then b=a.

So the answer is 5^1/5.

Hope it helps!

2007-07-06 15:47:26 · answer #2 · answered by ? 6 · 0 0

Raise both sides to b
5 = b^5
b = 5^(1/5)

2007-07-06 15:28:25 · answer #3 · answered by kellenraid 6 · 0 0

log_b 5=5 take anti log of both sides
5=b⁵ take ln of both sides
ln 5=5 ln bdivide both sides by 5
ln b=0.2*ln 5=0.32188758248682007492015186664524
b=e^0.32188758248682007492015186664524
b=1.379729661461214832390063464216

2007-07-06 15:49:27 · answer #4 · answered by yupchagee 7 · 0 0

tee hee hee

2007-07-06 16:23:05 · answer #5 · answered by Poetland 6 · 0 0

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