please help
2007-07-06 11:58:22 · 4 answers · asked by Bianca B 1 in Science & Mathematics ➔ Mathematics
Break up 108 into prime factors.
108 = 2 x 54
= 2 x 2 x 27
= 2 x 2 x 3 x 9
= 2 x 2 x 3 x 3 x 3
Now, use the property sqrt(abc) = sqrt(a) sqrt(b) sqrt(c).
sqrt(108) = sqrt(2 * 2) sqrt(3 * 3) sqrt(3)
And remember that the square root of the product of a pair of identical factors is just a singular one.
= 2 * 3 * sqrt(3)
= 6sqrt(3)
2007-07-06 12:02:05 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
You have to have a handy table of perfect squares around or do a "salami" routine. Having the former, I note that 36 * 3 = 108, so the answer is 6 sqrt(3)
2007-07-06 19:05:01 · answer #2 · answered by cattbarf 7 · 1⤊ 0⤋
you first divide by 2 which give you 54
then you divide by 2 again which gives you 27
because you use 2 as a divisor 2 times you make it a coeficient, which is a number in front of the sq rt.
27 divided by 3 = 9 again = 3
so the final answer is 6*sqrt of 3
2007-07-06 19:04:42 · answer #3 · answered by Archmage 2 · 0⤊ 0⤋
108. what "puggy" said is accurate but not necessarily right. If one were to simplify this they would need to find what goes into this number times itself like four goes into16 four times. I just spent moment trying to solve your problem and could not get it sorry.
2007-07-06 19:26:46 · answer #4 · answered by gdluver 2 · 0⤊ 0⤋