Help with algebra question please!!!??

Question

Solve 4s^3-28s^2=72s

Answer 1

4s³ - 28s² = 72s

Transpose 72s

4s³ - 28s² - 72s = 72s - 72s

4s³ - 28s² - 72s = 0

Factoring out the higherst common nonomial factor

4s(s² - 7s - 18) = 0

Inside the parenthesis the middle term is - 7s

the first term inside the parenthesis is

s² = 1

Find the sum of the middle term

multiply the first tern 1 times the last term 18 equasl 18 and factor

factors of 18

1 x 18
2 x 9. . .←. ,.use these factors
3 x 6

- 9 and + 2 satisfy the sum of the middle term

Insert - 9x and + 2s into the equation

4s(s² - 7s - 18) = 0

4s(s² - 9s + 2s - 18) = 0

4s[s(s - 9) + 2(s - 9)] = 0

4s(s + 2)(s - 9) = 0

- - - - - - - - -s-

Answer 2

Subtract the 72s from both sides to give 4s^3-28s^2-72s = 0.
Factor out 4s to give 4s(s^2-7s-18) = 0.
Factor the part in the brackets into (s-9)(s+2). Now you have
4s(s-9)(s+2) = 0. One of the three factors must equal zero.
The equation has three solutions, since any one of the factors could equal zero. Either s=0 (first factor) or s=9 (second factor) or s= -2 (third factor). OK?

Answer 3

Rewriting as 4s^3-28s^2-72s, we can factor:
4s*(s-9)*(s+2)

so are solutions are s=0 or s=9 or s=-2

Answer 4

4s^3-28s^2=72s
4s^3 - 28s^2 - 72s = 0
4s(s^2 - 7s - 18) = 0
4s(s -9)(s + 2) = 0
s = 0, s = 9, or s = -2.

Answer 5

4s(s^2-7s-18)

s=0 s=9 s= -2

Answer 6

4s^3-28s^2-72s
Or 4s(s^2-7s-18)=0
Or 4s{s^2+2s-9s-18}=0
Or 4S{S(s+2)-9(s+2)}=0
or 4s(s+2)(S-9)=0
Or s=0,s=-2&s=9 ANS.

Answer 7

4s^3-28s^2=72s
s=0OR
4s^2-28s=72
s^2-7s=18
s^2-7s-18=0
s=-9,2answer

Answer 8

Rackbrane's answer is on the spot.

Answer 9

people above and below me are right.