i know there is adam brody
shirly temple (spelling is wrong)
2007-07-06 08:11:19 · 17 answers · asked by liveit 1 in Entertainment & Music ➔ Celebrities
Famous people with lisps
Jonathon Ross
Brian Walden
Winston Churchill
Sean Connery
Anuerin Bevan
Many Japanese people Chinese, and Spanish people
Roy Hattersley
Mr Lonympics
Mike Tyson
Frank Bruno
Chris Eubank
Daffy Duck
2007-07-06 08:14:44 · answer #1 · answered by Michelle 2 · 1⤊ 1⤋
Celebrities With Lisps
2016-11-11 02:55:13 · answer #2 · answered by ? 4 · 0⤊ 0⤋
For the best answers, search on this site https://shorturl.im/OscWU
In a show called Zoey 101, Abby Wilde plays a person with a lisp. I don't know if she was acting it out but i think she has a lisp. don't worry about it, they aren't bad. =]
2016-04-01 00:44:19 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Reggie Bush has a lisp
2007-07-06 08:15:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Russell Simmons has a slight lisps
2007-07-06 08:17:10 · answer #5 · answered by Cyborg 57821-Cindi Mayweather 2 · 0⤊ 0⤋
Do you have a lisp?
I have a bit of one myself.
Humphrey Bogart, Winston Churchill, Truman Capote, and Thomas Jefferson all had lisps.
2007-07-06 08:14:08 · answer #6 · answered by Anonymous · 1⤊ 0⤋
This Site Might Help You.
RE:
famous people with lisps?
i know there is adam brody
shirly temple (spelling is wrong)
2015-08-06 17:50:32 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Barbara Walters
2007-07-06 08:14:09 · answer #8 · answered by Maureen K 2 · 0⤊ 0⤋
i think paula abdul has some sort of speech impediment...it might be a lisp she is trying to conceal...i dunno...that girl got problems...
and, there was the heavy chick from facts of life...can't remember her name...
also, Don Vito from Viva La Bam has some kinda stutter...not a lisp...what about joe pesci? he might lisp
2007-07-06 08:14:35 · answer #9 · answered by j c 3 · 1⤊ 0⤋
Ohh my god noo way adam brody out of the oc?? thats soo hot, i didnt even notice. also chris brown has a gawjus lisp!
2007-07-06 08:15:52 · answer #10 · answered by roaaaarrrrr 4 · 0⤊ 0⤋