At 126 K and 21 atm, compute the molar volume of oxygen gas assuming it is an ideal gas.
2007-07-06 07:24:20 · 0 answers · asked by g2hn 3 in Science & Mathematics ➔ Chemistry
pV = nRT
molar volume n=1
so V= RT/P R=8.31 T=126 21 atm =21*101325=2127825
V= 8.31*126/2127825=4.92*10^-4m^3= 0.492L
2007-07-06 07:33:26 · answer #1 · answered by maussy 7 · 0⤊ 1⤋
Molar Volume Formula
2016-12-13 09:46:59 · answer #2 · answered by tobias 4 · 0⤊ 0⤋
How To Find Molar Volume
2016-09-28 02:09:36 · answer #3 · answered by boyes 4 · 0⤊ 0⤋
PV = nRT will work for your problem, you can ignore the virial coefficients, since this is an ideal gas.
V = nRT/P
n = 1
R = 0.0821 L.Atm/mol.K
T = 126 K
everything cancels except the liters unit
I get 0.493 L at 126 K and 21 atm
2007-07-06 07:36:19 · answer #4 · answered by Izzy F 4 · 1⤊ 0⤋
molar volume at STP = 22.4 liters.
22.4 x (126/273.15) x (1/21) = .492 liter = 492 ml
2007-07-06 07:31:20 · answer #5 · answered by Mark H 3 · 0⤊ 0⤋