(m+n)^2 = (m+n)*(m+n)
= m*(m+n) + n*(m+n)
= m^2 + mn + mn + n^2
= m^2 + 2mn + n^2
2007-07-06 06:20:37
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answer #1
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answered by Dr D 7
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Write it this way since squared is really just multiplying it by itself.
(m+n)^2 = (m+n)(m+n)
You can FOIL method for the answer now.
First, Outside, Inside, Last
= m^2 + mn + mn + n^2
Add together anything that's the same & this is as far as you can go.
= m^2 + 2mn + n^2
The book may be trying to show you that you can do this quickly once you see the pattern.
It's the first squared, 2 of the outside & inside combined and then the last squared.
This will eventually get easier for you and the technique speed up the whole process for future use in higher level math.
Hope that helps :)
2007-07-06 06:23:18
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answer #2
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answered by Reese 4
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what are you asked to do with it? If you are asked to expand it then it is done like so:
(m+n)^2 = (m+n)*(m+n)
use the FOIL method to get:
m^2 +mn+mn+n^2 = m^2 +2mn+n^2
hope that helps
2007-07-06 06:21:45
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answer #3
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answered by Jon M 3
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the subject remember is mixtures. you like to confirm how many mixtures of four human beings you will get out of 8. In basic math words, you like to discover 8C4. Typing that in the process your medical calculator grants you the respond. right here is the way you do the working. kind of available 4-man or woman communities out of 8 pupils = 8C4 8C4 = (8x7x6x5)/(4x3x2x1) = 1680/24 = 70 mixtures.
2016-11-08 08:08:12
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answer #4
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answered by Anonymous
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you need to FOIL it:
First
Outer
Inner
Last
that means when to added numbers are squared, add the sum of the First numbers multiply, the Outer numbers multiplied, etc.:
(m + n)(m + n)
(m)(m) + (m)(n) + (n)(m) + (n)(n)
m^2 + 2mn + n^2
2007-07-06 06:29:04
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answer #5
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answered by Link 4
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(m+n)^2 = (m+n)*(m+n)
= m*(m+n) + n*(m+n)
= m^2 + mn + mn + n^2
= m^2 + 2mn + n^2
2007-07-06 06:22:29
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answer #6
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answered by zohair 2
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let's say for example m = 2 and n = 3
then
''' (2 + 3)
X (2 + 3)
-----------------------------
'''''''''' 6 + 9
''' 4 + 6
------------------------
= 4 + 12 + 9
= 25
so
''''' (m + n)
X (m + n)
-----------------------
'''''''''''' mn + n^2
m^2 + mn
----------------------------
m^2 + 2mn + n^2
2007-07-06 06:36:24
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answer #7
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answered by spirit dummy 5
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(m+n)^2 = (m+n) x (m+n)
= mm + nn + nm + nm
= m^2 + 2nm + n^2
2007-07-06 06:38:17
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answer #8
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answered by arthur g 2
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(m + n)²
= (m + n).(m + n)
= m.(m + n) + n.(m + n)
= m² + mn + nm + n²
= m² + mn + mn + n²
= m² + 2 mn + n²
2007-07-06 07:10:17
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answer #9
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answered by Como 7
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