how do i find the solution set ?

Question

-9 <=x<=-3 or x >= 1

x < 5

what would the solution of x ?

I am confused to find it because there is a OR .

so , how do i find the solution set ? what are the values ?

---------------------

there was also x<5 which you ignored

Answer 1

Mathematically, the solution can be written as:
[-9,-3] U [1, +∞) where 'U' is the mathematical symbol for a union.

Edit, since i missed the second inequality, I now modify my answer to [ -9,-3] U [1, 5)

Answer 2

On a number line put a dot (filled in) at - 9, -3, and +1. Put a dot (not filled in) at +5. Now draw a solid line between -9 and - 3, and a solid line between 1 and 5.
This shows you the domain of x is all numbers between and including -9 and -3. And also all numbers between and including +1 and +5 but not including 5.

Answer 3

You taking number theory? Look at each one indepently - then find the set of values that is common to each.

First, x >= 1 AND x<5, Therefore what solves that is 1<= x < 5

And the 2nd, is obvious that -9<=x<=-3 satisfies all x<5

The two cannot be related because there is no intersecting set.

I suspect you have mis-stated the problem. (Or else, I am getting too old.)

Ron.

Answer 4

-9 <=x<=-3 or x >= 1

Graph this on a number line. The solution is exactly what the inequalities say: EITHER -9 <=x<=-3, OR x >= 1. This gives two non-overlapping portions of the number line.

Answer 5

Do not be confused. There must be an OR, because x only have one value. So it can't be an AND.

Answer: -9<=x<=-3 or 1<=x<=5

Answer 6

the "or" is just stating that the two inequalities (-9 <= x <= -3 and x >= 1) are exactly the same.

so you've got the two inequalities:

x >= 1 and x < 5

the solution set is just: [1,5)

that is, all the numbers from 1 to 5 including 1, but not including 5.

Answer 7

I am confused too. What you wrote looks like answer, not like question. Where is the problem to be solved?