2007-07-06 06:08:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First determine the molecular weight of ethanol.
C2H5OH --> 46
100 gram of liquor would contain 45 grams of ethanol (45/46 =0.978 mole) and 55 grams of water. The molality of the ethanol is-
0.978 moles ethanol /0.055 kg water = 17.8 molal.
The freezing point depression contant for water is 1.86
The freezing point depression is 1.86 x 17.8 = 33 degrees C.
The freezing point estimate is -33 deg C.
2007-07-06 06:41:48 · answer #1 · answered by skipper 7 · 0⤊ 0⤋
between
-10 and -25 (in Fahrenheit)
or
-23 and -32 (in degree Celsius)
Because of its very low freezing point than that of mercury, it is sometime used in thermometer to measure the temperature change which is even below -40 c.
Increase in mass of ethanol will increase the van der waals forces between the molecules which means freezing and boiling points will increase too.
2007-07-06 13:43:52 · answer #2 · answered by crazystudent11 1 · 0⤊ 0⤋
Data required.
2007-07-06 13:36:21 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋
You would have to know the volume of the liquor you are using. :)
2007-07-06 13:59:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋