use the pythag. formula:
a^2 + b^2 = c^2 (where a = 8 and b = 6) to find the length of c (which is the longest diagonal of his pool)
c = 10m
there are 1000 m in 1 km, so he must swing 100 diagonals:
1000/10 = 100
2007-07-06 05:32:36
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answer #1
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answered by miggitymaggz 5
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Per the pythagorean theorem, the diagonal is determined by
a²+b²=c²
So the diagonal c=â(6²+8²) = 10m
Since the diagonal is 10m he needs to swim 100 diagonals to complete 100*10m = 1km
2007-07-06 12:33:42
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answer #2
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answered by Astral Walker 7
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Use Pythagorean theorem to find the length of a diagonal.
8^2+6^2=c^2
c=10
So he is swimming 10 meter long diagonals. 1 km=1000m, so he needs to swim 100 diagonals.
2007-07-06 12:32:51
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answer #3
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answered by Red_Wings_For_Cup 3
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You're looking for the hypotenuse of a right-angled triangle here.
8^2 + 6^2 = x^2
100 = x^2
x = 10 m
So,
10(x) = 1000 (10 which is the length times 'x' (how many) to get to 1000)
1000/10 = x
100 = x
Therefore 100 diagonals = 1 km
2007-07-06 12:33:39
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answer #4
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answered by de4th 4
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He would have to swim the same diagonal 100 times where back and forth counts as two diagonal paths. Also, he would have to swim the same path over and over since in order to swim different diagonal(s), he would have to travel across either a length or a width.
2007-07-06 12:35:55
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answer #5
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answered by gfulton57 4
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d² = 8² + 6²
d² = 64 + 36
d² = 100
d = 10 m
No. of diagonals = 1000 / 10 = 100
2007-07-06 17:50:56
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answer #6
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answered by Como 7
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Find the pool's diagonal (a^2 + b^2 = c^2) you have both 'a' and 'b'.
1000 meters divided by the lenght of c.
2007-07-06 12:32:39
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answer #7
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answered by Tom 2
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The diagonal is 10m.
1000m/10m = 100 diagonal lengths.
2007-07-06 12:32:25
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answer #8
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answered by Mark 6
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Hi. That is a 3,4,5 triangle. (3x2=6, 4x2=8, 5x2=10) so the diagonal is 10m. 1,000m divided by 10m = ?
2007-07-06 12:31:49
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answer #9
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answered by Cirric 7
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8m by 6m = 4800x0.0001= ??????
2007-07-06 12:50:04
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answer #10
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answered by cinammon l 2
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