(5x+3)/(4x) = (x+1)/(x) Please Solve!!!! I am stuck?

Question

O.o

ok..

Ummm.... I really need this answered -_- Stupid packet work.

Answer 1

(5x+3)/(4x) = (x+1)/(x)

x is not equal zero (why?)

(5x+3) * x = 4x * (x+1)

5 x + 3 = 4 x + 4

x = 1

Answer 2

x=1

Answer 3

-x + 6 - 5x = 14 - 2r 6 - 6x = 14 - 2r 3 - 3x= 7 - r -3x = 4 - r 3x = -4 + r x = (r-4)/3 2(2x + 3) = -6(x + 9) 4x+6 = -6x - fifty 4 6 + fifty 4 = -10 x 60 = -10x -6 = x 7 - (-4t) = 4t - 14 - 21t 7 + 4t = 4t - 14 - 21t 7 = 14 - 21t -7 = -21t -7/-21 = t a million/3 = t -3/4x + 5 = a million/4x - 3 -3x + 20 = x - 12 20 + 12 = 4x 32 = 4x 8 = x

Answer 4

(5x+3)/(4x) = (x+1)/(x)

Method-1:
cross multiplying we get

(5x+3) * x = (x+1)*4x
5x^2 + 3x = 4x^2 + 4x
5x^2 + 3x - 4x^2 - 4x = 0
x^2 - x = 0
x*(x - 1) = 0
=> x = 0 or 1.

Substituting back the values of x, we see that x cannot be 0 because we get into the 'divide by zero' situation. Hence x = 1 is the only solution.

Method-2: (5x+3)/(4x) = (x+1)/(x)

Multiply 'x' on both sides we get,

(5x+3)/4 = x+1
5x+3 = 4(x+1)
5x+3 = 4x+4
5x-4x = 4-3
x = 1.

Answer 5

(5x+3)/(4x) = (x+1)/(x)
x(5x+3) = 4x(x+1)
5x^2 + 3x = 4x^2 + 4x
x^2 - x = 0
x(x-1) = 0
x = 0 or x = 1

x = 0 rejected because denominator cannot be 0.
Therefore, the only solution to the equation is x = 1.

Answer 6

(5x+3)/(4x) = (x+1)/(x)

x is not equal zero (why?)

(5x+3) * x = 4x * (x+1)

5 x + 3 = 4 x + 4

x = 1

Answer 7

First u cross-multiply, it becomes
x(5x+3) = 4x(x+1)
5xsq + 3x = 4xsq + 4
xsq + 3x - 4 = 0

Then you factorize and you get
x = 1 and x = -4

Good luck!

Answer 8

Both sides of the equations have a factor of x in the denominator. Start by multiplying both sides of the equation by 4x. Keep in mind that since you have x in the denominator the system is undefined if x = 0.

Good Luck

Answer 9

Uno