[H+]=2*10^-2 M
How do you calculate the pH value of the above?
2007-07-05 21:27:22 · 9 answers · asked by Michael 2 in Science & Mathematics ➔ Chemistry
pH = - log [H+]
= - log 2 x 10^-2
= 2 - log 2
= 1.7
2007-07-05 21:49:19 · answer #1 · answered by Papilio paris 5 · 0⤊ 0⤋
Calculation Of Ph Value
2016-12-11 16:31:06 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The pH value is calculated by the formula:
pH = -lg [H ions]
[H+] = -lg 2*10^-2
=1.69897
= 1.7 ( to 1 dp)
2007-07-05 21:39:14 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Apply the formula:-
pH = -log[H+]
= - log[2*10^-2]
Do the clculation as followed in ur country.
2007-07-05 23:26:20 · answer #4 · answered by sillu s 2 · 0⤊ 0⤋
pH = log 1/[H+] = log 1/2*10^-2 = log 50 =1.7
2007-07-05 21:34:36 · answer #5 · answered by maussy 7 · 0⤊ 1⤋
if HCO3- IS 223 mg/l and CO2 is 60 mg/l what will be the ph of the water
2014-11-21 04:07:51 · answer #6 · answered by mohd 1 · 0⤊ 0⤋
It was doubled because sulphuric acid has two replacable hydrogen. and HClO4 dissociates in two steps again giving two H+ ion.
2016-03-19 05:39:54 · answer #7 · answered by Anonymous · 0⤊ 0⤋
[H+]=6.24*10^6
2013-11-12 06:07:32 · answer #8 · answered by Anonymous · 0⤊ 0⤋
oh my days!...and i thought i knew chemistry :P..
(sorry im no help :P)
2007-07-05 21:48:15 · answer #9 · answered by robinjayne 2 · 0⤊ 1⤋