is this equation even or odd?

Question

y= (x^3) / ( (x^2) - 1)

y equals x cubed divided by x squared minus one

the question asks whether this equation is even or odd? What does that mean? help?

Answer 1

lets say f(x) = (x^3)/((x^2 - 1)

if f(-x) = f(x) .......then its an EVEN function
if f(-x) = -f(x)......then its an ODD function

Just substitute a value for x and use the above conditions to assess whether the function is odd or even.

Your function is ODD as f(-2) = -8/3 = -f(2)

there u go.

Answer 2

A function is even if and only if f(x) = f(-x).
A function is odd if and only if f(-x) = -f(x)

All we have to do is test. Remember that
f(x) = x^3 / (x^2 - 1)

Test for even:

f(-x) = (-x)^3 / ( (-x)^2 - 1 )
f(-x) = -x^3 / (x^2 - 1), and as you can see, f(x) is not equal to f(-x); therefore, the function is not even.

Test for odd: Calculate f(-x), and compare this to -f(x). But since we've already calculate f(-x) above, let's calculate -f(x) and compare.

-f(x) = - [ x^3 / (x^2 - 1) ]
-f(x) = -x^3 / (x^2 - 1)

And as you can see, they are the same; that is
f(-x) = -f(x)
Therefore, the function is odd.

Answer 3

Odd

Answer 4

An even function is symmetric about the y-axis. An odd function is symmetric about the origin. This equation is neither even nor odd.

Answer 5

odd

Answer 6

wow no clue...sorry
try hotmath.com
find your book it they have it
and you can find the problem