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A triangle has one 90 degrees angle and from there one leg is 10.25 long and the other leg is 7.75 long. what are the degrees for the other two angles. Thank you

2007-07-05 17:09:57 · 8 answers · asked by clemaube 1 in Science & Mathematics Mathematics

8 answers

tan x = 10.25/7.75
x = inverse of tan (10.25/7.75)

tan y = 7.75/10.25
y = inverse of tan (7.75/10.25)

tan = opposite/side
cos = side/ hippotaneus (whatever the other part is called)
sin = opposite/ hippotaneus

2007-07-05 17:17:05 · answer #1 · answered by cherry 5 · 0 0

SohCahToa
Sin = opposite / hypotenuse
Cosine = adjacent / hypotenuse
Tangent = opposite / adjacent

x = angle adjacent to the 7.75 leg
y = angle adjacent to the 10.25 leg

tan x = 10.25 / 7.75
x = arc tan (1.323)
x = 52.91 degrees

y = 90 - 52.91
y = 37.09 degrees

because all angles in a triangle must add up to 180 degrees

2007-07-05 17:30:26 · answer #2 · answered by Anonymous · 0 0

Take your friendly trig tables and find the angle that corresponds to 10.25/7.75; that's the larger of the two acute angles. The other is 90-that angle.

2007-07-05 17:15:14 · answer #3 · answered by cattbarf 7 · 0 0

Assume you have a triangle with indices A, B and C

the angles of A and B are directly across from the sides of the triangle a and b respectively

C is the right angle and side c is directly across from it.

see web site listed below for a visual

you have the values for a and b
a = 10.25
b = 7.75

using Pythagorean's theorem a^2 + b^2 = c^2 so
c = sqrt(a^2 + b^2)
c = sqrt(10.25^2 + 7.75^2) = 12.85

now knowing the size of the sides and the properties of sine and cosine we can solve for A and B

sin A = a/c => inv sin(a/c) = A
sin B = b/c => inv sin(b/c) = B


A = inv sin (a/c) = inv sin (10.25/12.85) = inv sin(0.7977) = 52.9 deg

B = inv sin (b/c) = inv sin (7.75/12.85) = inv sin(0.6031) = 37.1 deg

verify values A + B = 90

52.9 + 37.1 = 90 degs it works

Hopes this helps

2007-07-05 17:20:52 · answer #4 · answered by Navidad_98 2 · 0 0

Let these two angles be a & b

tan a = 10.25/7.75= 1.322
calculate a

tan b = 7.74/10.25=0.756
calculate b

2007-07-05 17:17:16 · answer #5 · answered by Jain 4 · 0 0

remember SOHCAHTOA
Sine of an angle = Opposite side / Hypotenuse
Cosine of an angle = Adjacent side / Hypotenuse
Tangent of an angle = Opposite side / Adjacent Side

Solve for the angle
If you have more questions, email me at ladybug777_2@yahoo.com

2007-07-05 17:19:57 · answer #6 · answered by ladybug777_2 1 · 1 0

one angle is tan inverse(31/41)


so obviously other would be pie/2-tan inverse(31/41) which is equal to tan inverse(41/31)


hope this will help u ]

thankyou

2007-07-05 18:23:19 · answer #7 · answered by Anonymous · 0 0

Try studying the Unit Circle.

2016-04-01 10:46:42 · answer #8 · answered by Maria 4 · 0 0

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