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Q.1 A ball is thrown vertically upward from the ground with a speed of 25 m/s. On its way down it is caught at a point 5m above the ground. How long did the trip take?

Q.5 The time period of a pendulum is 2 seconds at the surface of the earth calculate its time period on the surface of the moon where the value of acceleration due to gravity is one-sixth that of the value of ‘g’ at the surface of the earth.

Q.7 If a diffraction grating produces a first order spectrum of light of wavelength 6*10^-7 m at an angle of 20 from the normal: calculate the number of lines per mm.

2007-07-05 16:53:20 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

You can find examples of these in your text.
1) Vo = 25 m/s, Vf = 0 m/s, a = -9.80 m/s^2, this gives time for up. Then calculate distance for up. Finally us Vo = 0 m/s, a = 9.80 m/s^2, and d = distance calculated above - 5 m. Use this info to calculate time for down. Add together.

2) T = 2(pi)(sq rt of L/g) g(earth) = 9.80 m/s^2, g(moon) = 1.6 m/s^2

2007-07-05 19:56:45 · answer #1 · answered by physandchemteach 7 · 0 0

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