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A rocket is launched from rest and moves in a straight line at 70 deg above the horizontal with an acceleration of 46 m/s^2. After 30s of powered flight, the engines shut off and the rocket followsa parabolic path back to earth.(a) Find the time of flight from launching to impact on earth.(b) What is the maximum altitude reached? (c) What is the distance from launch pad to impact point?

2007-07-05 15:28:51 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Is the given accleration before or after considering the gravitational accleration of the earth?

2007-07-05 15:33:18 · answer #1 · answered by cattbarf 7 · 0 2

It facilitates us to make certain which you have tried it your self. right here is a few concepts: a million. artwork out the gap travelled ((at^2)/2, a=40m/s^2 and t=27s), and the suitable velocity (v=at). 2. Use trig (cos and sin) to artwork out the preliminary place (top and horizontal distance) relative to the beginning (launch pad), besides because of the fact the preliminary horizontal and vertical velocity. 3. First look on the vertical. you recognize the preliminary top (h0), the preliminary vertical velocity (v0) and the acceleration (g). So h(t) = h0+v0t-(gt^2)/2. looking the optimal of this materials the optimal altitude. looking whilst h(t)=0 (take the constructive answer) tells you the time from powering off the engines to result. 4. ultimately, use the time from powering off the engines to result and the preliminary horizontal velocity to make certain the gap travelled. reliable success.

2016-10-20 00:19:06 · answer #2 · answered by Anonymous · 0 0

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