With pressure constant, the temperature of a gas is increased from 30° C to 90°C. The volume will
a)triple
b)decrease by ½
c)increase by about 20%
d)remain the same
2007-07-05 10:44:22 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
a.
2007-07-05 10:46:43 · answer #1 · answered by gfulton57 4 · 0⤊ 6⤋
The volume will increase as the temperature goes up, but to get the amount you must convert the temperatures to Kelvin so the answer is (90 + 273) / ( 30 + 273) = 363/303 = 1.2 so the volume increased by 20%
2007-07-05 10:47:49 · answer #2 · answered by rscanner 6 · 3⤊ 0⤋
Volume and temperature are directly proportional. Think of heating a balloon. The volume will expand.
The only tricky part is that you have to use Kelvin for the temperature and not Celsius. So the temperature is increasing from 303 K to 363K.
That would be a 20% increase.
2007-07-05 10:47:59 · answer #3 · answered by reb1240 7 · 1⤊ 0⤋
c). This is Charle's Law. (T & V are Directly Proportional)
363/303 = 1.20 ....The volume will increase by 20%.
2007-07-05 10:51:47 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋
The blended gas equation is PV/T = P'V'/T'. If one element is held consistent, you will discover what the relationship between the different 2. to that end, P is persevering with, so the equation is V/T = V'/T' (do no longer overlook to apply absolute temperatures)
2016-11-08 06:19:55 · answer #5 · answered by newnum 4 · 0⤊ 0⤋
You need to convert to Kelvin first.
30C + 273.15 = 303.15K
90C + 273.15 = 363.15K
Now, with constant pressure:
V1/T1 = V2/T2
V1T2/T1 = V2
V1(363.15)/(303.15) = V2
(1.198)V1 = V2
(119.8%)V1 = V2
So it increased by 19.8%. The answer is c.
2007-07-05 10:49:26 · answer #6 · answered by Anonymous · 0⤊ 0⤋