Assuming constant temperature, what volume would a gas occupy at 82.3 kPa if the volume is 344 cm3 at 110 kPa?

Answer 1

Boyle's Law....Pressure increase <===> Volume Decrease.
At constant temperature.
P1xV1 = P2xV2
82.3kPa x V1 = 110kPa x 344cm³
V1 = (110 x 344) ÷ 82.3
New Volume (V1) = 37,840 ÷ 82.3 = 459.8cm³

(Alternatively, 110 ÷ 82.3 = 1.34. Therefore, 344 x 1.34
= 459.8cm³ )

(The ideal gas law and the combined gas law, are derived from Boyle's, Charles' and Gay Lussac's laws. These laws deal with only one of two or (combined gas law, three P, V or T), variables and a constant (P, V, or T), as the question indicates).

(cattbarf, your answer proves my argument.
PV/T [one set]= PV/T [second set]...Insn't this the Combined Gas Law ??? and simplified further P1V1T2 = P2V2T1).

Answer 2

BennyJ- These are all based on the Ideal Gas Law. This goes PV=nRT, for a given set of PVT data. As long as n is NOT CHANGED, you can simplify this to:
[PV/T]one set = [PV/T]second set.
In this case, we keep T constant so this reduces to [PV]one set = [PV] second set.
We want to find V of second set. We have all other data. Go for it.

Answer 3

u can simply use ideal gas law

PV =nRT

n R and T are constant so

P1V1=P2V2

344*110 = 82,3*V2

Answer 4

257 cm^3