uuh solving for X but involving logs/lns?

Question

this is very hard to type out but i'll try my best.

find the value of each expression:

a) [both logs have base 2] 2^(log(4)+log(6))


b) e^(3ln(2))


any help would be great! thanks

Answer 1

(a)
log(4) + log(6)
= log( 4*6 )
= log(24).
With logs to base 2, 2^log(24) = 24.

(b)
e^(3 ln 2)
= [ e^(ln 2) ]^3
= 2^3
= 8.

Answer 2

2^(log(4)+log(6))
= 2^log_2 (24) = 24

e^(3ln(2)) = e ^ln(2^3) =2^3 = 8

Answer 3

rearrange your method