just a tease
2007-07-05 09:14:53 · 5 answers · asked by DC 1 in Science & Mathematics ➔ Mathematics
As the line is perpendicular to y = (-2/3)x + 6, its gradient is 3/2.
The equation is therefore:
y = 3x/2 + c
with c chosen so that when x = 2, y = 5.
That means:
5 = 3 + c
c = 2.
The equation is y = 3x/2 + 2.
2007-07-05 09:19:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Line is perpendicular to the line y=-2/3x+6
so slope = 3/2
so equation is y=3/2x +b
finding b by putting (2,5)
5 = 3/2 (2) +b
b = 5-3
b = 2
so equation of line is y = 3/2 x +2 or
2y = 3x+4
2007-07-05 16:20:50 · answer #2 · answered by sweet n simple 5 · 0⤊ 0⤋
y= -2/3x + 6 1/3
2007-07-05 16:19:40 · answer #3 · answered by bluecuriosity 2 · 0⤊ 0⤋
Gradient of given line = (- 2/3)
Gradient of perpendicular line = m,where:-
m x (- 2/3) = - 1
m = 3 / 2
Equation of perpendicular is:-
y - 5 = (3/2).(x - 2)
y - 5 = (3/2).x - 3
y = (3/2).x + 2
2007-07-09 11:56:40 · answer #4 · answered by Como 7 · 0⤊ 0⤋
y = 3/2x + 2
2007-07-05 16:18:22 · answer #5 · answered by Nterprize 3 · 0⤊ 0⤋