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what is the concentration of sugar(C12H22O11) in mol L^-1 if its 20g are dissolved in enough water to make a final volume up to 2L

2007-07-05 08:43:44 · 2 answers · asked by harry 1 in Science & Mathematics Chemistry

2 answers

(20g sugar)/(342.34 g/ml sugar) = .058 mol sugar

(.058 mol sugar)/(2L) = .03M

2007-07-05 08:49:49 · answer #1 · answered by Wheels 3 · 1 0

Atomic weights: C=12 H=1 O=16 C12H22O11=342

Let sugar be called S.

20gS/2L x 1molS/342gS = 0.058gS/L to two sig figs.

2007-07-05 15:50:57 · answer #2 · answered by steve_geo1 7 · 0 1

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