Solve by factoring.?

Question

1.x^2-5x+6=0
2.2x^2-9x-5=0
3.3x^2+5x-2=0

Answer 1

1. factor using trial by error (x-2)(x-3)+0, set both factors equal to 0: x-2=0, x-3=0, solve and you get x=2 and x=3, so your answer should look like this: 2 or 3.
2. this is a little more difficult, but possible
start like this: (2x-_) (x+_), you may have to switch the signs,
then find factors of 5, 5 and 1, plug them in where you think they go and see if it works, you should get (2x+1)(x-5), do the same thing i did for the first one to solve and get your answers.
3. I think you can do this one by yourself

Answer 2

1.x^2-5x+6=0
(x - 3)(x + 2) = 0
x = 3, x = -2

2.2x^2-9x-5=0
(2x + 1)(x - 5) =
2x + 1 = 0 >> 2x = -1 >> x = -1/2
x - 5 = 0 >> x = 5

3.3x^2+5x-2=0
(3x - 1)(x + 2) = 0
3x - 1 = 0 >> 3x = 1 >> x = 1/3
x + 2 = 0 >> x = -2

Answer 3

(x - 2)(x - 3)= 0 x = 2 or 3

(2x +1)(x - 5) =0 x=-1/2 or 5

(3x - 1)(x + 2) =0 x = 1/3 or -2

Answer 4

1.x^2-5x+6=0
(x-2)(x-3)=0
x=2, 3

2.2x^2-9x-5=0
(2x+1)(x-5)
x=-1/2, 5

3.3x^2+5x-2=0
(3x-1)(x+2)=0
x=1/3, -2

Answer 5

x² - 5x + 6 = 0

x² - 3x - 2x + 6 = 0

x(x - 3) - 2(x - 3) = 0

(x - 2)(x - 3) = 0

- - - - - - - - -

2x² - 9x - 5 = 0

2x² - 10x + x - 5 = 0

2x(x - 5) + 1(x - 5) = 0

(2x + 1)(x - 5) = 0

- - - - - - - -

3x² + 5x - 2 = 0

3x² + 6x - x - 2 = 0

3x(x + 2) - 1(x + 2) = 0

(3x - 1)(x + 2) = 0

- - - - - - - - -s-

Answer 6

1.x^2-5x+6=0
(x-6)(x+1)=0
so x= 6 or -1

2.2x^2-9x-5=0
(x-5)(2x+1)=0
x= 5 or -1/2

3.3x^2+5x-2=0
(x+2)(3x -1)=0
x = -2 or 1/3

Answer 7

1. (x-3) (x-2)
2. (2x+1) (x-5)
3. (3x+1) (x+2)

Answer 8

1.(x-3)(x-2)
2.(2x+1)(x-5)
3.(3x-1)(x+2)