(x - 2)(x-2)
x(x-2) -2(x-2)
x^2 -2x -2x +4
x^2-4x+4
or simply use the formula (a-b)^2 =a^2+b^2 -2ab
so x^2 +2^2-2(x)(2)
x^2 -4x+4
2007-07-05 07:24:06
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answer #1
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answered by sweet n simple 5
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FOIL it
F - First
x * x = x^2
O - Outside
x * -2 = -2x
I - Inside
-2 * x = -2x
L - Last
-2 * -2 = 4
Then combine like terms
x^2 + -2x + -2x + 4 = x^2 -4x + 4
2007-07-05 14:27:31
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answer #2
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answered by Anonymous
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FOIL (F is for first, multiply the first number in each parenthesis together to get x times x is x^2) (O is for outer, multiply the two outter terms together such as x times -2 to get negative 2x) (I is for inner, multiply the inner terms together such as -2 times x to get another negative 2x) (L is for last, you multiply the last terms together to get -2 times -2 to get positive 4) (add up all the components together to get x^2 - 4x + 4!)
2007-07-05 14:29:11
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answer #3
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answered by Anonymous
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you use the F.O.I.L method
this is what we did.. its just a way of factoring
you multiply the first two (F) so thats x^2 (or x squared)
then the outside two (O) so thats -2x
then the inside two (I) so thats -2x
then the last two (L) and thats -4
so then you combine what you get which is
(x^2) + (-2x) + (-2x) + (-4) = x^2 -4x-4
and thats your answer! i think you can also use the quadratic equation.
or you can factor by grouping...
2007-07-05 14:35:00
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answer #4
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answered by Anonymous
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(a-b)(a-b)= a^2-2ab+b^2 [Commit this to memory]
(x-2)(x-2) = x^2-4x +4
2007-07-05 14:27:59
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answer #5
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answered by ironduke8159 7
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Yes, the FOIL method!
2007-07-05 14:30:14
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answer #6
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answered by PYT 3
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x2-4x+4 is this the answer you were looking for?
2007-07-05 14:31:30
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answer #7
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answered by Ferdiyana A 2
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