how do you find the x and y intercepts?of this graph 4x+2y=8?

Answer 1

x-intercept
let y=0
4x=8
x=2
y-intercept
let x=0
2y=8
y=4
EASY!!!

Answer 2

The first thing to do, is to put the equation into the form y=mx+b where m is the slope and b is the y-intercept (you'll see why in a moment).

So, 4x + 2y = 8 Now subtract 4x from each side of the equation and you get:

2y= -4x + 8 Now divide by 2 on both sides of the equation, and you get:

y = -2x + 4

So, the y-intercept is 4. This is because the y-intercept is defined as the point where x=0. Substitute x=0 into the equation and you get 4.

Now, to get the x intercept (the value of x when y=0), substitute 0 for y and solve for x. So, you get:

0 = -2x + 4 substract 4 from both sides and you get:
-4 = -2x now divide by -2 on both side and you get:

x=2

So, the y-intercept is (0,4) and the x-intercept is (2,0)

Answer 3

Y intercept

X = 0

4x + 2y = 8

4(0) + 2y = 8

0 + 2y = 8

2y = 8

2y / 2 = 8 / 2

y = 8 / 2

y = 4

The y intercept is 4

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x Intercept

Y = 0

4x + 2y = 8

4x + 2(0) = 8

4x + 0= 8

4x /4 = 8 / 4

x = 8 / 4

x = 2

x intercept is 2

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Answer 4

First extract the y variable to the left side. Then create a table with x variables - have 5 or 6 of them. Then add them to the equation and there you have x/y variables ready for the graph. Now draw up x and y coordinate and feel up the variables that you have. Connect the dots, and its ready. This looks like a parabole, but im not sure. Anyway, i think i gave you a little more then you need.

Answer 5

for y-intercepts put x=0 in the equation
i.e 2y=8
y=4

similarly
x=2

r the intercepts