An astronaut on the moon fires a projectile from a launcher on a level surface so as to get maximum range.?

Question

If the launcher gives the projectile a muzzle velocity of 25m/s, what is the range of the range of the projectile? [ hint: the acceleration due to gravity on the moon is only one sixth of that on the earth.]

Answer 1

Hi. The correct angle for maximum range on the Moon is 45 degrees. (On Earth is is slightly higher to get the projectile into thinner air sooner. No air? No adjustment.) Get the gravity value for the Moon. (Hint: It is probably NOT one sixth exactly.) Then just arithmetic.

Answer 2

Break the muzzle velocity v into vertical and horizontal components. Vy = v sin theta Vx = v cos theta time aloft = 2(Vy)/g horizontal progress = time aloft times Vx = 2 (Vy)(Vx)/g = 2 V^2 cos (theta) sin (theta) / g = sin (2 theta) v^2 / g This is obviously maximized when theta = 45 degrees, so the sine is one. So Max range = v^2 / g Don't forget the moon's g is one-sixth the earth's (9.8 m/s^2), so the range is six times as far.

Answer 3

Do your own homework.