can some one show me how this graphing works 2y=x+4? this needs to be graphed?

Answer 1

Solve for y:
y=(1/2)x+2
The graph is a line with slope 1/2 and y-intercept of 2.
Draw the axis and put a point at (0,2).
Slope = rise/run so rise = 1 and run=2.
Move your pencil 2 units to the right and up 1 to (2,3).
Draw a line through the two points.

Answer 2

Well, first things first, you should change it to basic slope-intercept form
y = mx + b

Where b is the y intercept (the point at which the line crosses the y axis), m is the slope of the line (how much it moves up or down as you follow the line), and x is the variable x.

You have
2y = x+4

Divide both sides by 2.

y = x/2 + 2

Now pick a few numbers in your head. Let's go with 0, 2, 4, and 6. Plug those into the equation as x values.

If x = 0, then the equation becomes:
y = 0/2 + 2
y = 2

So now you have a point on the line. x = 0, and y = 2.
You write that in this form:
(0, 2).

Let's try another one. Let's make x = 2

y = 2/2 + 2
y = 3
So we have
(2, 3)

For x = 4, we get (4, 4)

For x = 6, we get (6, 5)

So we have all of these points
(0,2), (2, 3), (4, 4) and (6, 5)

Plot those points on a graph, and connect them with a straight line.

Answer 3

Most graphing calculators will do this easily. First isolate, y:
y= (x+4)/2 or 0.5x + 2 (this is a line).

For a quick and dirty graph, plot a few points between (-5 and 5 for example) to get your x, y coordinates. You really only need two points, because it is a line, but you would do this operation for more complicated equations.

Example:
For x=0, y is (0 + 4)/2 = 2 [Your point to plot is (0,2)]
For x=-5, y is (-5+4)/2 = (-1)/2 = -1/2 [Plot (-5, -.5)]
For x=5, y is (5+4)/2=(9/2)=4.5 [Plot (5,4.5)]

I hope this is what you are looking for.

Answer 4

Rewrite the equation as y=x/2 + 2 and then you will see a line with slope 1/2 that intersects the x axis at -4. (Substitute y=0 and solve for x)

To see it, plot these points and draw a line through them

(-4,0)
(0,2)
(2,3)

The general form of the line is

y=mx + b

where m is the slope
and the y intercept is

x= -b / m.

Check out this page that I found by doing a search on y=mx+b

http://mathforum.org/cgraph/cslope/mxplusb.html

Answer 5

2y=x+4
Set x = 0 and get y=2 so (0,2) is a point on the line.
Set y =0 and get x = -4 so (-4,0) is a 2nd point on the line.
Draw aline between these two points extending it as far as you like in both directions. This is the required line. A straight lin is determined by two points.