i need help matching the equations with the correspoding vertical asymptotes
1.)1/x
2.)x/x^2-4
3.)5/x^2
the problem is i need help trying to figure out how to do it thank you i greatly appreciate your help!
2007-07-05 05:55:08 · 5 answers · asked by skate_freely 1 in Science & Mathematics ➔ Mathematics
Well, you can't divide anything by zero. It's just not allowed - and any point where you would be dividing by zero is a vertical asymptote. So like in #1, when x = 0, you have a vertical asymptote because you would be dividing by zero.
Same goes for #3.
#2 is a bit more interesting
0 = x^2 - 4
when x = 2 is when the denominator equals zero, thus a vertical asymptote. However, because it is squared, it can be +2 or -2. So you have two vertical asymptotes; one at +2 and one at -2.
2007-07-05 05:58:50 · answer #1 · answered by misscarinne 4 · 1⤊ 0⤋
1) for 1/x what you need to do is plug in numbers
If X=1 1/1=1 The only number that X can't be is zero. Anything divided by zero is undefined. So basically with those equations you need to find the number that will make the bottom number zero. X/X^2-4 Plug in 2 for X 2/2^2-4 2/4-4 Also on this graph there will be a negative 2. because any negative squared will be positive. I would try drawing the graphs though. For a beginner that is the best way to learn it helps a visual learner. Pick 4 numbers to plug in for X and get your Y. I usually pick the easy ones 0,1,2,3 Make sure to do the same thing with the negatives. So any time the equation ends up undefined, that is where your asymptotes will be...
2007-07-05 06:06:54 · answer #2 · answered by Ian R 3 · 0⤊ 0⤋
Data required.
2007-07-05 06:02:02 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 1⤋
Do your own homework
2007-07-05 05:58:04 · answer #4 · answered by Anonymous · 0⤊ 1⤋
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2007-07-05 05:57:18 · answer #5 · answered by :) 3 · 0⤊ 1⤋